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1. ABCD is a parallelogram. Points P and Q divides BC in three equal parts. Prove that

ar(APQ) = ar( DPQ) = 1/6 ar (ABCD).

2. traingles DAC and BAC are on same base AC. If vertex B and D are on opposite side of AC such that area of traingle BAC . Prove that OD=OB.

3. AB is a diametre of the circle whose centre is O. If angle ADC = 120 , calculate the angle BAC.

Please its urgent........

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by zeenat

arent three questions in one question too long?

hmmm seriously its too long

ya but interesting

hmmm

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