# The surface area of a sphere of radius 5 cm is stores the area of the curved surface area of cone of radius 4 cm .Find the height of the cone

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by laxmishak

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by laxmishak

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(5)²= slant height = 25cm

radius = r = 4cm

r² + h² = l²

h² = l²-r²

h² = 609

h = √609 = 24.67 cm = height of the cone

CSA(cone)=πr(r+h)

CSA(cone)=Ar(sphere)

4πr²=πrl

4(25)=4l

25=l

l=25cm

By using Pythagoras theorem

l²=h²+r²

h²=l²-r²

h²=25²-4²

h²=625-16

h=√609

h=24.67cm

Hence the height of cone is 24.67cm.