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A train covers 300 kilometre at a uniform speed If the speed had been 5 kilometre an hour more the journey would have taken 2 hours less find the speed of

Let the initial speed of the train be - x Increased speed = x+5 Distance covered in both cases = 300km Time taken in initial speed = Time taken in increased speed = Given, Time taken in increased speed = Time taken in initial speed -2 = = -2 = = By cross multiplying = 300(x) = (300-2x) (x+5) Just simplify and solve from here as a quadratic equation

Let x be the speed of train Time taken to cover 300 km = 300/x Increased speed = x+5 Time taken to cover 300 km when speed is increased to 5 km/hr = 300/ x+5

According to the question 300/x - 300/ x+5 = 2 ( 2 hrs less ) 300(x+5)- 300x / x(x+5)=2 300x + 1500 - 300x / x^2+5x = 2 1500/x^2+5x= 2 2(x^2+5)= 1500 2x^2+10 = 1500 2x^2+10-1500= 0 (divide by 2 ) x^2+5-750=0