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Given that abcd is a rhombus.
o is the centre
bo = do
we know that the diagonals of a rhombus are perpendicular bisector of each other
so, <aod = <cod = 90
<aod +<cod =90 + 90 
= <180
if the angle formed is 180 then it implies that it is a straight line.
so ao and co both lies on the same straight line
i think it helps u a lot.........
so......plz mark as brainliest
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