Answers

2016-03-08T14:59:46+05:30
No we cant Draw Triangle Having The Those Vertices Because The Given vertices seems To Be collinear  So a Traingle Cant Be Formed
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2016-03-08T16:08:52+05:30

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Area of triangle =  \frac{1}{2}[x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})

 \frac{1}{2}[1(8-14)+5(14-5)+13(5-8)]

 \frac{1}{2}[1(-6)+5(9)+13(-3)]

 \frac{1}{2}[-6+45-39]

 \frac{1}{2}[0]

= 0

Therefore, the given points are collinear.

Hence, a triangle cannot be formed with the given vertices. 
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