# The point D divides the side BC of triangle ABc in the ratio m:n prove that ar(triangle ABD):ar(triangle ADC)=m:n

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**ar(**Δ **ABD) = ½*B
* H**

**= ½ * BD *
AE **

**ar(**Δ **ADC) = ½
* B * H**

**= ½ * CD *
AE**

**Now, their ratio
:**

**½*BD*AE/1/2*CD*AE
= BD/CD **

**Therefore
BD/CD = BD : CD i.e m:n**

**Hence proved.
**

** **

**I hope it
helps……….**