Answers

2016-03-09T16:58:52+05:30
AO=OC
AD=BC
ANG.DAO= ANG.ACB(alternate angs)
therefore,triangleAOD~triangle BOC
OD=OB(cpct)
0
2016-03-09T18:23:09+05:30
Consider triangles AOD and BOC
AD =  BC (given)
OC = OD (given)
∠ADO = ∠OCB (Alternate interior angles)
therefore, 
ΔAOD is congruent to ΔBOC
Hence, AO = OB (C.p.c.t.)
0