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In ∆ ABC,
AB = AC(Given)
AD = AD (Common)
Therefore, ∆ADB ~ ∆ADC
(By SAS)
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In triangle ADB and triangle ADC
  angle DAB= angle DAC [bcoz AD bisects angle A]
  AD=AD [common]
So,by SAS
  triangle ADB ~ triangle ADC
    Hence showed
see picture for more explanation

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