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you have proved that ar( ABF ) = ar ( EAC )
2 ar ( ABF ) = ar (  ARHF ) ----------------(1)
( since they are on the same base and between the same parallel )
2 ar (EAC ) = ar ( ABDE ) ---------------(2)
comparing (1) and (2)
we get that
ar ( ARHF ) =ar ( ABDE )

i hope it helps.....................
3 4 3
thank you
my pleasure
how to mark your answer as brainliest
when some body will add another answer to ur question..or/ if they don't then after 1 month u will be notified ! n then after 1 month u can mark my answer as the best :)
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