Answers

2016-03-10T21:16:26+05:30
Thickness of hemispherical bowl =0.25 cm

inner radius of hemispherical bowl=5 cm

outer radius of hemispherical bowl = (5+0.25) cm
                                                        =5.25 cm

outer curved surface area of the bowl=2
 \pi  r^{2}
                                                           =6.18*5.25*5.25
                                                           =6.18*27.5
                                                           =170.33
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2016-03-10T21:51:10+05:30
Inner radius =5cm
thickness=0.25cm
so,outer radius=5+0.25
=5.25cm
outer c.s.a=2×pi×r^2
=2×3.14×5.25^2
=6.28×441/16
=173.0925cm^2
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