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A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm, find the outer curved surface area of the bowl. (Take pie=3.14)



Thickness of hemispherical bowl =0.25 cm

inner radius of hemispherical bowl=5 cm

outer radius of hemispherical bowl = (5+0.25) cm
                                                        =5.25 cm

outer curved surface area of the bowl=2
 \pi  r^{2}
1 5 1
bhai bhai mene jalte type kardeya copy me mene ab wapas deka
2ke jage 1 lekdeya
i am not able to edit
no problem
Inner radius =5cm
so,outer radius=5+0.25
outer c.s.a=2×pi×r^2
0 0 0
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