Answers

2016-03-11T10:38:12+05:30
What should be added 4a²-a² to get b²-4a²
     ( 
4a²-a²) +x = (b²-4a²)
      x = (b²-4a²) - (4a²-a²)
        =   b²-4a² - 3a²
       =   b² -7a²
0
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2016-03-11T10:43:41+05:30
If only to add then add 
-7 a^{2} + b^{2}

solution of above
     ( 
4a²-a²) +R = (b²-4a²)
the value to be added
      x = (b²-4a²) - (4a²-a²)
        =   b²-4a² - 3a²
       =   b² -7a²
0
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