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PQ is chord of length 6 cm of the circle of radius 6 cm. TP and TQ are tangents to the circle at points P and Q respectively. Find Angle PTQ.



Take center of circle as O
join OP,OQ
PQR forms a triangle
so now, OP=OQ=PQ
therefore it is an equilateral triangle
angle POQ=60
angle POQ+angle PTQ=180
therefore angle PTQ=120
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