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Let ABCD be a rhombus
AC and BD are diagonals.
AC=6, BD=8
diagonals of a rhombus bisect each other at right angles.
consider AC and BD meet at O
then in triangle AOD,
AD² = AO² + OD²
= (AC/2)² + (BD/2)²
= 3² + 4²
= 25
AD = √25
AD=5=side of rhombus
therefore perimeter of rhombus is 20cm.

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hope it helps you...
plss mark it as brainliest....
diagonals of a rhombus bisect each other at 90' therefore.................
( see the attach figure )

perimeter of a rhombus = 4*side =4*5 = 20 cm
i hope it helps............... 
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