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The atomic number of Al is 13 and that of Cl is 17.​how many electrons, protons, neutrons, are present in Al 3+ and Cl - ions.



In the ion Al 3+ it losses 3 electrons.
Therefore the electrons present in it is 13 - 3 = 10 electrons.
In the same way in the Cl- atom it losses one electron therefore the no. of electrons in Cl- is 17-1 = 16
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