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Yes. It is possible to construct a triangle with the given measurements. Step 1: draw the constant base I.e QR=7cm. Step 2: construct ∠R =45° on point R. Step 3: extend ∠R to mark point P. I.e RP = 5cm. Step 4: join PQ. Measure PQ which will be = 5cm The construction will be like this
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LET SIDES BE x,x+5,7
sum of two sides should exceed third side
and it satisfies
x+7>x+5 and so on

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