# If A(-3, 5), B(-2, -7), C(1, -8) and D(6,3) are the vertices of a quadrilateral ABCD, find its area

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by d9eepkaurPAD

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by d9eepkaurPAD

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Area of triangle

=1/2[-3(-7-3)-2(3-5)+6(5+7)

= 1/2 [-3×-10 -2×-2 +6×12]

=1/2 × 30 +4 +72

=1/2×106

=53cm

in triangle BCD

area of triangle

=1/2 [-2(-8-3)+1(3+7)+6(-7+8)

=1/2[-2×-11 +10+6]

=1/2×22+10+6

=1/2×38

=19 cm

so,area of quadilateral=area of triangle ABD+area of triangle BCD

=53+19 = 72 cm²