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A leap year consist 366 days , that is, 52 complete weeks and two days remain. These 2 days can be any of the following
     (mon,tues) (tues,wed) (wed.thu) (thu,fri) (fri.sat) (sat,sun)
Thus, total no. of cases = 7
no. of cases in which we get a friday = 2
therefore, probability of getting 53 fridays in a leap year = 2/7
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