Answers

2016-03-13T23:59:39+05:30
Let ABCD be a rhombus
diagonals :-
AC= 8cm
DB=15 cm
let AC and DB meet at a point O
AD² = AO² + OD²
AD² = 4² + 7.5²
AD² = 16 + 56.25
AD² = 72.25
AD = √72.56
AD = 8.5
HENCE, EACH SIDE OF THE RHOMBUS IS 8.5 CM....

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