# A sphere and right circular cylinder of same radius have equal volume .by what percent does diameter of cylider exceed its height???please sir reply fast

its vry urgent for me

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its vry urgent for me

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Given sphere and a right circular cyclinder of the same radius.

Volume of Sphere = (4/3)πr3

Volume of right circular cyclinder = πr2h

Given Volume of Sphere = Volume of right circular cyclinder.

(4/3)πr3 = πr2h

(4 /3) r = h.

2r = 3h / 2

d = 3h / 2

Now, let h be 100 %.

D = 3h/ 2 = (3/2)x 100% = 150%

So, required difference = 150% - 100% = 50%

Hence, diameter of the cylinder exceed its height by 50%.

The Brainliest Answer!

volume of cylinder = volume of sphere

pir²h= 4/3pi r³

H=4/3r

2r=3h/2

D=3h/2 { D beath diametre of cylinder}

D=3h/2=3/2*100%= 150%

so required difference= 150-100%=50%

hence diameter of cylinder exceed its height by 50%