Answers

2014-02-26T14:50:40+05:30
\frac{2^{x-1}*4^{x+1}}{8^{x-1}}=

={2^(x-1) x 2^(2x+2)}/2^(3x-3)

=[2^(x-1+2x+2)]/2^(3x-3)

=[2^(3x+1)]/2^(3x-3)

=2^(3x+1-3x-3) = 2^(-2) = 0.25
0