# A triangle and a parallelogram are on the same base and between the same parallels.if altitude of triangle is 4 cm and it 's area is 8cm^2 ,find the length of base of parallelogram.

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area of triangle = 8cm sq. ( i.e 1/2 ar of ||gm)

2*8= 4*b ( 2*ar of triangle = ar of ||gm or base* height)

16=4h

h=16/4

h=4cm

Verify

if a triangle and a parallelogram are on the same base and between the same parallels, area of triangle= 1/2 area of ||gm.

therefore,

8=1/2*4*4

8=16/2

8=8

therefore, base of the parallelogram is 4 cm. pls mark as 5 stars if this helped! I spent lot of time solving this 4 u.