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Let original diameter be d that is 2r new diameter=3/4d or 3/2r original CSA 4*pi*r^2 =4*pi*4r^2=16*pi*r^2 new CSA=4*pi*9/4r^2 =9*pi*r^2 decrease=7*pi*r^2 decrease℅=(7*pi*r^2/16*pi*r^2)*100 =43.75℅
1 5 1
then try !!..
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Let original diameter be 2x
then radius =x
decreased diameter of sphere=2x-25% of 2x
decreased radius=3/4x
so,decreased c.s.a=
decrease in area=
so, decreased percentage in c.s.a=7/4×pi×x^2/4×pi×x^2×100%=7/16×100%=43.75%
2 5 2
then what
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