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Compound A having molecular formula c3h7cl reactive to alcoholic koh.compound B having molecular formula c3h6 BE AN additional reaction with HBr GIVES

C.find A,B AND C


In case of compound A , as it is reactive to alcoholic Cl , the Cl group must not be present at the terminal.

As there are only three carbons, the compound will be 2-chloropropane(H_3C-CHCl-CH_3).

In case of compound  B, on seeing the formula we can say it is an alkene.
NOTE :- C_nH_{2n} = C_3H_{2*3}

Therefore the compound B will be Propene (H_2C=CH-CH_3)

According to Markonikov Rule compound C will be 2-bromopropane (H_3C-CHBr-CH_3)

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A is isopropyl chloride CH3CHCLCH3 it can also be npropyl alcohol CH3CH2CH2CL
then it reacts with alc. KOH and eliminates HCL to form propene CH3CH=CH2 THIS IS compound B then B reacts with HBr to give isopropyl bromide that is CH3CHBrCH3
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