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The average salary of employee in the company is rupees 5000 Per month. average salary of 5 manager is rupees 6000 and the average salary of workers is rs

2500.find the no . of worker present in a company.



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Let the number of workers be x
(total salary of employee)/(x+5) = 5000
⇒total salary of employee = 5000(x+5)
(total salary of manager)/5 = 6000
⇒total salary of manager = 6000×5
(total salary of workers)/x = 2500
⇒total salary of workers = 2500x
total salary = total salary of workers +total salary of manager
                   = 2500x +6000
∴[5000(x+5)] = 2500x +6000×5
⇒5000x + 25000 = 2500x + 30000
⇒2500x =5000
⇒x =2
number of worker is 2
0 0 0
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