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Two parts of a number are such than one is half the other . the sum of the two parts is 8 more than their difference . what are the part and what is the

One is half the other => x=y/2 the sum of the two parts = 8 more than their difference ie x+y = 8 + (x - y) on solving the equation x+y -x +y = 8 2y = 8 => y = 4 so, x = 4/2 = 2

so , 2 numbers are 2 & 4 Check the solution I condition => x = y/2 2 = 4/2 II condition x+y = 8 + (x-y) 2+4 = 8 +(4-2) 6 = 8 + 2 ie 6(sum of the 2 no.) = 8 + (more than the difference)