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In the given fig. PQR is the tangent to a circle at Q whose centre is O.AB is a chord parallel to PR and Angle BOR =60*.find angle AQB

:l I think it should be BQR that's why
Like this one http://m.meritnation.com/ask-answer/question/pqr-is-the-tangent-to-a-circle-at-q-whose-center-is-o-ab/math/3655894
no divya in question paper its given as BOR
I think if u have took it from learncbse m.the question maybe wrong m.I don't know sorry bye!
its ok....btw i took it from EAD....


Angle AQB = half of angle BOR
sub the values and get the answer by intercepted angle theorem
0 0 0
why AQB is half BOR....can u state the reason please
construction of BOR
refer chap circle of std X of CBSE Board
Ull get it
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