Answers

2016-03-16T19:02:26+05:30
D1=150km
s1=x km/hr
t1=150/x hr
d2=200km
s2=20+x km/hr
t2=200/(20+x)hr
ATQ:
150/x+200/20+x=5

(3000+150x+200x)/x2+20x=5
3000+350x=100x+5x2
3000+250x=5x2
5x2-250x-3000=0
x2-50x-600=0
a=1
b=-50
c=-600
=(50+70)/2
=60 km/hr
=(50-70)/2
=-10 km/hr
Since a negatine can't be the value of speed, the speed of the truck calculated is 60 km/hr.




   
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