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2016-03-16T23:27:44+05:30

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According to the balanced equation.
2 moles of Al(54kg) gives 2 moles of Fe(112kg).
So for 1120 kg of Fe we need  540 kg of Al.
2 5 2
2016-03-17T15:53:17+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
As per the equation
2 mol of Aluminium + 1 mole of Iron Oxide -----> 1 mole of Aluminium Oxide + 2 moles of Iron

1 mole of aluminium = 27 U
1 mole of Iron Oxide =  56*2 +16*3 = 160U

1 mole of Aluminium Oxide = 27*2 + 16*3 = 102U

54U  +  160U  →  102U+112U 54  g  +  160g  →  102g+112g As  per  the  balanced  equation  54g For  112g  of  iron,  we  required  54g  Aluminum  for  1120  kg  of  iron  required  aluminum  is-

(1120*1000) *54 =540000 gram 
so it is 540 kg

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