# Two concentric circles of radii a and b (a>b) are given. Find the length of the chord of the larger circle which touches the smaller circle

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by nbvjanmallu

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by nbvjanmallu

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by Pythagoras theorem

OC^2=OE^2+CE^2

a^2=b^2+CE^2

√(a^2-b^2)=CE

CD=2CE[perpendicular drawn from centre bisect the chord]

CD=2√(a^2-b^2)