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A(x,x-2) , B(x+23,x+2) and C(x+3,x) The area of the triangle is 1/2[x(x+2-x)+(x+23)(x-(x-2))+(x+3)(x-2-(x+2))] =1/2[2x+2x+46-4x-12] =1/2(34)=17 sq.cm Therefore the area of the triangle is 17 sq.cm and Hence the area is independent of x