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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let an equilateral triangle Δ ABC : AB = BC = AC. vertices are A(3,2) and B(-3,2) and C(x,y). The mid point of the side AB is M (0,2). (AB)² = (3+3)² + (2-2)² = 6² + 0² = 36 AB = 6 cm AB = BC = AC = 6 unit. AM = 3 unit. As two vertices are A(-3,2) and B(3,0) so that Third vertex will be at Y-axis(x=0). so that Third vertex C(0,y) and it is located below the origin. Hence it contains the origin. Now,

y² = (AC)² - (AM)² ⇒ y² = 6² - 3² = 36 - 9 =27 y = √27 = 3√3 unit Hence Third vertices of the triangle are A(-3,2) , B(3,2) and C(0,3√3).