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A roller 140 cm long has a radius of 35 cm .to level the playground it takes 980 complete revolutions. determine the cost of levelling the playground at

the rate of 75 paisa per square metre.


First we need to find the surface area of the roller
=2x22÷7x35x140 =30800cm^2 or 3.08m^2
so 1 revo = 30800cm
980 = ?
30184000cm^2 or
so 3018.4x75=226380 or ₹ 2263.80
2 4 2
Surface area of roller=2πrl =2π×35×140 30787 Total area=30787*980 30171855 Cost 0.75*30181855 Rs22628891
0 0 0
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