Answers

2016-03-17T20:18:21+05:30
Given  , convex mirror

R = 3 cm

object distance ( u ) =  - 5 cm

f = 1.5 cm [ f = R / 2 ]
 
we know that ,  \frac{1}{f} =  \frac{1}{v} +  \frac{1}{u}

so

 \frac{1}{1.5} =  \frac{1}{v}  - \frac{1}{5}

so

  \frac{1}{v} =  \frac{1}{1.5}  +  \frac{1}{5}

V = 1.15

the image is at a 1.15 cm distance from the mirror on the opposite side

Size of the image  = Magnification =  \frac{v}{u}
            
                                                           =  \frac{1.15}{(-5)}
                                              
                                                             = 0.23

Hence the size of the object is 0.23 times of the object

The Image is diminished , errect and Virtual

Thanks !!!!!!


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