Answers

2016-03-17T20:17:17+05:30
The given quadratic equation⇒kx²-14+8=0
Let the roots of the equation be a and b
a=6b

a+b=-(-14)/k          (-coeff. of x/coeff. of x²= sum of the roots)
7b=14/k
b=2/k⇒1

ab=8/k                    (constant/coeff. of  x²= product of roots)
6b²  =8/k
6(2/k)² =8/k
24/k²  =8/k
k=3

Therefore the value of k is 3


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