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Some hot water was added to 3 times the mass of cold water at 10 degree Celsius and the resulting temperature was found to be 20 degree Celsius. What was

the temperature of the hot water?
is mass of cold water = 3 times the mass of hot water



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Mass of hot water = M.  let its temperatur be T  deg C
mass of cold water = 3 * M    three times mass of hot water.
cold water is at 10 deg C
final temperature = 20 C
  So WRITE equation for balancing the Heat energy
       M T  + 3M 10  =  (M + 3M) 20
     = M T + 30 M  =  4M * 20 = 80 M          cancel M
     T + 30 = 80            T = 50 deg Centigrade

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