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The Brainliest Answer!
2016-03-18T12:04:52+05:30
A (1,-1), B(-4,2k) and C (-k,-5)

ArΔABC = 1/2 [x1 (y2-y3) + x2 (y3-y1) + x3 (y1-y2) ]
         24 = 1/2 [1(2k+5) + -4(-5+1) + -k(-1-2k)
         24 = 1/2 [2k+5 + 16 +(k+2k²)]
         24 = 1/2 (2k+5+16+k+2k²)
         24 = 1/2 (2k² +3k +21)
         48 = 2k² +3k + 21
         2k²+3k-27 = 0
        2k² + 9k - 6k - 27 = 0
  or   2k² - 6k + 9k - 27 =0
        2k(k-3) + 9(k-3) = 0
        (2k+9) (k-3) = 0

∴ k = -9/2 or 3 



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3 5 3
It was wrong i corrected it!
ya I hv also got this answer
Thank you