The length of a plastic box is 1.7m, width is 1.5m and is 0.65m high. What is the longest rod that can be placed in the box? Find its TSA and CSA

2
it's be the diagonal of that box ... :P .. sry but too lazy to solve
Sheesh I didn't knew ur lazy!!!!!!(Don't worry I'm the greateset lazy!)XD

Answers

2016-03-18T13:20:28+05:30
TSA OF THE BOX =2lbh =2*1.7*1.5*0.65
                                          =3.315m
CSA OF THE BOX =2h(l+b) =2*0.65(1.7+1.5)
                                              =3.17m
0
2016-03-18T13:26:47+05:30
given :
length = 1.7 m
width = 1.5 m
height = 0.65 m 

need to find out :
1. TSA of the box
2.  CSA of the box
3. the longest rod that can be placed in the box

solution :
1. TSA of the box :
TSA of cuboid = 2 ( lw + hw + hl )
⇒ 2 ( 1.7 * 1.5 + 0.65 * 1.5 + 0.65 * 1.7 )
⇒ 2 ( 9.265 )
⇒  18.53 m ²

2. CSA of the box :
CSA of cuboid = 2h ( l + b )
⇒ 2 * 0.65 ( 1.7 + 1.5 )
⇒ 2 * 0.65 ( 3.2 )
⇒ 1.3 ( 3.2 )
⇒ 4.16 m ²

3. the longest rod that can be placed in the box :
formula = √( l² + b² + h² )
⇒ 2.268 m ²
∴ the longest rod that can be fit in the box would be of 2.268 m ²
1 5 1
sorry i've made a mistake in the last answer about the longest rod that can be places in the box
the longest rod that can be placed will be " root over 2.268 sq.cm "
I'm really sorry for the mistake I've done at last ...!
:3