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Prove that determinant 1 b b+c 1 a a squared

1 c c+a = det. 1 b b squared
1 a a+b 1 c c squared
are you sure the question is correct? they do not seem to be equal



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Determinant on LHS  =
1 (ca+cb-ac-a²) - 1 (ab+b²-ab -ac) + 1 (bc+ab-bc-c²)
= ab+bc+ca - (a²+b²+c²)

determinant on RHS =
a² (c-b) - b²(c-a)+c²(b-a)

they do not seem to be equal ...

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