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The taxi fare in a city is as follows: for the first km ,the fare is Rs. 10 and for the subsequent distance, it is Rs. 8 per km . taking the distance

covered as y km and total fare as Rs.x ,write a linear equation for this information.


Fare for the first kilometer =  10
susequent distance = 8 

x = 10+8(y-1)
0 0 0
Let the total fare be Rs x km
Let the total distance be x km.
Now, ATQ
fare for the total distance is Rs 10
Subsequent distance is Rs 8
So, y=10+8×(x-1)
y= 10+8x-8
0 0 0
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