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Assuming we are talking about log_{10}(x).

Since, log_{10}(10) = 1.

I can write my equation as : log_{10}(2)+log_{10}(10)

Now, remember the identity; log_{10}(a*b)=log_{10}(a)+log_{10}(b).

I'll leave the final answer upto you.
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As we know that log (x x y) = log x + log y. =} given equation = log 2 + 1 As one can be written as log 10 to the base 10.. Eqn will be log2 + log 10.
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