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2016-03-21T04:52:34+05:30

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Let AC and BD meets at O. sides of OAB are 8,10 and 12 Area of triangle OAB, =) √15(15-8)(15-10)(15-12) =)15√7 =)(1/2)x12xOM, where OM is perpendicular to AB, OM=(5√7)/2 Distance between AB and CD=5√7 AREA of ABCD=2 x AREA of BCD =2(1/2)x12x5√7 =60√7 units
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