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An equilateral triangle has all three interior angles 60°.

⇒ Draw a straight line, PQ that will be one leg of the angle. 

⇒ With a compass on P, Set the width half of PQ

⇒ Draw an arc above P and crossing PQ

⇒ Where the arc crosses PQ, make an arc across the first. 

⇒ Draw a straight line toward the x. 
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i know the construction thanxx for that but i need the justification . how to prove its 60 degree...?
oh. opps
Let me edit my answer then
Join DE ( pt at the base and 60 degree pt...u will get ADE as triangle )

AD=AE(radii of same arc)    - 1ST
AD=DE(arc of same radius) - 2ND
from 1 and 2
in triangle as all the 3 sides are equal..therefore it is an equilateral triangle...

by angle sum property of triangle,

therefore A=E=D=60
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