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Three particles each of mass 10 g are placed at the vertices of an equilatral triangle of side 30 cm. Find Distance of its centre of mass from any of its



Center of mass will be at the Centroid of the equilateral triangle.
Length of perpendicular = √[a²-(a/2)²] = (a√3)/2
The centroid divides the perpendicular into 2:1
distance of center of mass from vertex = (2/3)×(a√3)/2 =a/√3
                                                              = 30/√3 = 10√3 cm

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