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Two Digit palindromes should contain both digits same.

So,total no of two digits palindromes = 9 (11,22,33,...99)
To find 3 digit palindromes we will go with Permutations.

To become a 3 digit number palindrome 1st and 3rd digit should be same..(1_1,2_2,3_3.....9_9)

So this place can be filled in 9 way (number must not start with 0)

Second place can be filled with 10 ways (_0_,_1_,_2_,...._9_)

So total no of three digit palindromes =9×10=90

Now,1001 is the only one four digit palindrome between 10 and 1010

So, Total = 9 + 90 + 1 = 100
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ok these rfrom various exams
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i have a group of frndz on whatsapp. they upload various question they get troubled from
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