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2016-03-25T18:45:23+05:30

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Let
Present age of Father = f
Present age of Son = s 

Two years ago
f-2=s-2
Father was 3 times as old as his son 
f-2=3(s-2)
f-2=3s-6
f=3s-6+2
f=3s-4............(1)
and 2 year hence,
f+2=s+2
then twice his age will be equal to 5 times that of his son
2(f+2)=5(s+2)

2f+4=5s+10
2f=5s+10-4
2f=5s+6.............(2)
Put the value of f in (2) from (1)
2(3s-4)=5s+6
6s-8=5s+6
6s-5s=6+8
s=14
Put the value of s in (1)
f=3s-4............(1)
f=3(14)-4
f=42-4
f=38 
Present age of Father = f = 38 years old
Present age of Son = s = 14 years old 
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2016-03-25T18:45:35+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Two years ago, Let the age of father be f years
and the age of son be s years
A/q
f= 3s
and , 2(f+4) = 5(s+4)
putting f= 3s
⇒2(3s+4) = 5(s+4)
⇒6s +8 = 5s +20
⇒s = 12
so present age of son = 14 years
and present age of father = 12×3 +2 = 38 years
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