# A boy 1.6m tall is 20m away from a tower and observes that the angle of elevation of the top of the tower is 60 degree. Find the height of the tower.

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DE=1.6m as BC =1.6 m

DC =20 m as BE = 20 m

so, in triangle ABE

tan 60= AB/BE

√3 =AB/20

AB =20√3m

so,the height of the tower = AC =AB+BC =20√3+1.6

=20×1.732+1.6 =34.64 +1.6

=36.24 m

The Brainliest Answer!

see the link for the figure of the question

let AB be the height of tower and CD be the boy

we have CD = 20m and CD = 1.6m

also BD = CE = 20m

in triangle ACE ,

tan60 = P/B = AE/20

√3 = AE/20

so, AE = 20√3m

also CD = BE = 1.6m

Height of tower = AE+BE

=(20√3+1.6)m