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2a+1/2a=2a/2a      +      1/2a[in binomial divided by monomial,each term of binomaial is to be divided by monomial]
ans=1    + 1/2a

their cube by identity [a+b]3 =a3+b3+3a2b+3ab2
let1/2a be a          1 be b
their cube=1/2a cube+1 cube+3*1*1/2a*1+3*1*1/2a*1/2a
is the answer

please mark as brainliest
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