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## Answers

The Brainliest Answer!

Let AC = 6 and BD = 8

property Diagonals of rhombus bisect each other in right angle.

consider AC and BD meet at O

THen in triangle AOD

AD² = AO² + OD²

= (AC/2)² + (BD/2)²

= 3² + 4²

= 25

AD = √25

AD = 5 side of rhombus

Perimeter = 4 × side = 20 cm