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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let ABCD be rhombus
Let AC = 6 and BD = 8
property Diagonals of rhombus bisect each other in right angle.
consider AC and BD meet at O
THen in triangle AOD
AD² = AO² + OD²
= (AC/2)² + (BD/2)²
= 3² + 4²
= 25
AD = √25
AD = 5 side of rhombus
Perimeter = 4 × side = 20 cm

Well diagonals of a rhombus bisect each other If u draw the diagram u would find four triangles. In any triangle u coupd apply the Pythagoras theorem
ABCD is rhombus with AC and BD as the diagonal intersecting at O. So AO=CO=3cm and BO=DO=4cm
Aplly Pythagoras theorem in triangle AOB where angle AOB = 90 degress since diagonals of rhombus are perpendicular to each other . let the required side be X cm
In traingle AOB
Square of AB= square of AO + square of BO
AB square = 3*3 +4*4
AB square = 25
AB = 5 cm
Hence side is 5 cm