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Rationalise the eqn
(3+5i)/(1+2i) x (1-2i)/(1-2i)
(3-6i+5i10)/1+4              {∵ (a+b)(a-b) = a² -b²}
⇒(13- 1i)/5
(x+yi) ⇒13/5 -1/5i
0 0 0
he asked conjugate of it, the answer is (13/5)+i(1/5)
oh yeah , right
when u conjugate the signs will change to _ n then follow the same procedure.
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