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Let the numbers be a,b,c,d,e
By the problem,(a+b+c+d+e)/5=27
Let the exclude number be 'a'
Substituting (2) in (1),
Therefore,the exclude number is 35.

1 5 1
27=x/5 where x is the sum of 5 numbers of the given mean                          x=135   but given that one no is excluded and mean is reduced by 2           therefore mean=27-2=25                                                                                25=y/4 where y is sum of numbers of mean after excluding one number     y=100                                                                                                              excluded number=x-y=135-100=35
1 4 1
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